Q. Find out the BMD and SFD value of a Cantiliver beam of length l subjected to udl throughout a span.
Shows a Cantiliver AB fixed at A and free at B carrying a uniformly distributed load of w per unit run over the whole length.
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A. Cantiliver:
Consider any section X distance x from the end B.
S.F. at X = Sx = + wx
B.M. at X = Mx = – wx. x/2
Mx = – wx²/2
Hence, we find that the variation of the shear force is according to the a linear law, while the variation of the bending moment is according to a parabolic law.
At x = 0, Sx = 0;. At x = 0, Mx = 0;
At x = l, Sx = + wl
At x = l, Mx = – Wl² /2
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